# ETOOBUSY đźš€ minimal blogging for the impatient

# Area of a triangle, again

**TL;DR**

How the triangleâ€™s area should be really calculated.

In Area of a triangle I described a way to calculate the area of a triangle with a formula that I â€śderived myselfâ€ť - in the sense that I wanted to solve that problem and used my past maths knowledge. This is what I ended up with:

\[S = \frac{ \sqrt{ (\vec{v}\cdot\vec{v})\cdot(\vec{w}\cdot\vec{w}) - (\vec{v}\cdot\vec{w})\cdot(\vec{v}\cdot\vec{w}) } }{2}\]It turns out that the world consistently beats (most of) us, so I found Area of Triangles and Polygons that provides this instead:

\[S' = \frac{v_x \cdot w_y - v_y \cdot w_x}{2} \\ S = |S'|\]This is so amazing and superior:

- no square roots, how cool can that be?
- the result is
*signed*, which gives us an idea of whether $\vec{v}$ is on the â€śrightâ€ť or the â€śleftâ€ť of $\vec{w}$, which might come handy.

Awesome! Soâ€¦ code time again (I also played a bit with the inputs to cut one line out):

```
sub triangle_area {
my ($v_x, $v_y) = ($_[1][0] - $_[0][0], $_[1][1] - $_[0][1]);
my ($w_x, $w_y) = ($_[2][0] - $_[0][0], $_[2][1] - $_[0][1]);
return ($v_x * $w_y - $v_y * $w_x) / 2;
}
```