# ETOOBUSY đźš€ minimal blogging for the impatient

# Double Dobble - easy optimization

**TL;DR**

A quick optimization over the quest for Double Dobble arrangements.

In previous post Quest for Double Dobbles I described a possible approach to finding Double Dobbles, with all the limitations.

One observation that allowed me to reduce the search time was that itâ€™s fine to always assume that the first index is $0$. Thanks to the rotation invariance, we can rotate any arrangement and make it so the first index is $0$.

It occurred to me that a similar reasoning can be also done to fix the following index to always be $1$. It works like this:

- the difference $1$ MUST appear exactly twice in a valid arrangement;
- hence,
*at least*two indexes MUST be adjacent (modulo $N$); - if we apply a rotation over this arrangement to put the one
*on the left*at index $0$, the other one goes into index $1$.

Hence, our iterator for possible combinations becomes this:

```
my $it = NestedLoops(
[
[0], [1],
map {
my $end = $N - 1 - ($k - 1) + $_;
sub { [($_ + 1) .. $end] },
} (2 .. $k - 1)
]
);
```

which brings us down to ${N - 2} \choose {k - 2}$ possible combination to look through.

For values of $k$ that indeed have a solution, this is not an improvement. I mean, if there is a viable arrangement, the variant starting with $(0, 1, â€¦)$ will be checked before all the others anyway.

The optimization comes handy when trying out values of $k$ that *do not*
have a solution:

```
$ time perl old-code.pl 8
real 0m17.382s
user 0m17.040s
sys 0m0.096s
$ time perl new-code.pl 8
real 0m4.126s
user 0m4.088s
sys 0m0.008s
```

I suspect that there may be other *low-hanging fruits* to further
enhance the searchâ€¦ who knows?!?

*Comments? Octodon, , GitHub, Reddit, or drop me a line!*